232. Implement Queue using Stacks
Leetcode Stack DesignImplement the following operations of a queue using stacks.
- push(x) -- Push element x to the back of queue.
- pop() -- Removes the element from in front of queue.
- peek() -- Get the front element.
- empty() -- Return whether the queue is empty.
Example:
MyQueue queue = new MyQueue();
queue.push(1);
queue.push(2);
queue.peek(); // returns 1
queue.pop(); // returns 1
queue.empty(); // returns false
Notes:
You must use only standard operations of a stack -- which means only push to top, peek/pop from top, size, and is empty operations are valid. Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack. You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
```Java class MyQueue { private int[] items; private int size; private int head; private int tail; private int len;
/** Initialize your data structure here. */
public MyQueue() {
items = new int[10];
size = 0;
head = 0;
tail = 0;
len = 0;
}
/** Push element x to the back of queue. */
public void push(int x) {
items[tail++] = x;
if (tail == size) {
resize(2*size);
}
len++;
}
/** Removes the element from in front of queue and returns that element. */
public int pop() {
len--;
return items[head++];
}
/** Get the front element. */
public int peek() {
return items[head];
}
/** Returns whether the queue is empty. */
public boolean empty() {
return (len==0);
}
private void resize(int newSize) {
int newItems[] = new int[newSize];
for (int i = head, j = 0; i <= tail; i++, j++) {
newItems[i] = items[j];
}
head = 0;
tail = items.length;
size = newSize;
items = newItems;
}
}
/* * Your MyQueue object will be instantiated and called as such: * MyQueue obj = new MyQueue(); * obj.push(x); * int param_2 = obj.pop(); * int param_3 = obj.peek(); * boolean param_4 = obj.empty(); / ```